[2t/ 2-5t^2]dt积分

问题描述:

[2t/ 2-5t^2]dt积分

∫2t/(2-5t²)dt
=(-1/5)∫d(5t-2²)/(5t²-2)
=(-1/5)ln(5t²-2)+C能再详细点吗?谢谢。∫2t/(2-5t²)dt=(-1/5)∫d(5t²)/(5t²-2)=(-1/5)∫d(5t²-2)/(5t²-2)=(-1/5)ln(5t²-2)+C