已知tanx=2,则sin2x+3cos2x/2COSX^2+3sin2x-1
问题描述:
已知tanx=2,则sin2x+3cos2x/2COSX^2+3sin2x-1
答
tanx=2 sinx=2/√5 cosx=1/√5
sin2x=2sinxcosx=4/5
cos2x=3/5
sin2x+3cos2x/2COSX^2+3sin2x-1=4/5+3*(3/5)/2(1/√5)^2+3*4/5-1=6.7