求y=sin(1/3x+pai/4),x属于r
问题描述:
求y=sin(1/3x+pai/4),x属于r
答
y=sin(1/3x+π/4)最大值是1,最小值是-1,最小正周期:6π
y=sin(1/3x+π/4)=sin1/3xcosπ/4+cos1/3xsinπ/4=√2/2(sin1/3x+cos1/3x)