极限的简单运算2设等差数列an的公差为2,前n项和为Sn,则lim ((an^2-n^2)/Sn)=?
问题描述:
极限的简单运算2
设等差数列an的公差为2,前n项和为Sn,则lim ((an^2-n^2)/Sn)=?
答
极限的简单运算2
设等差数列an的公差为2,前n项和为Sn,则lim ((an^2-n^2)/Sn)=?