(x^2-2x+3)^2=4x^2-8x+17写出详细过程!

问题描述:

(x^2-2x+3)^2=4x^2-8x+17写出详细过程!

((x-1)^2+2)^2=4(x-1)^2+13
令u=(x-1)^2, (u>0)可得
(u+2)^2=4u+13
u^2+4u+4=4u+13
u^2=9
u>0 所以u=3
(x-1)^2=3
x=1+/-[根号3]