10/40+(x—10)*(1/40+1/80)=1

问题描述:

10/40+(x—10)*(1/40+1/80)=1

两边*80得
20+(x-10)*(2+1)=80
(x-10)*3=60
x-10=60/3
x-10=20
x=20+10
x=30

0.25+(x-10)*3/80=1
3*(x-10)=80*(1-0.25)
x-10=20
x=30