计算[x/﹙xy+y﹚]·[﹙x²+x﹚/x²y]

问题描述:

计算[x/﹙xy+y﹚]·[﹙x²+x﹚/x²y]

原式=[x/y(x+1)][x(x+1)/x²y]
=[x/y(x+1)][(x+1)/xy]
=x(x+1)/xy²(x+1)
=1/y²

原式=x/y﹙x+y﹚·x﹙x+y﹚/x²y=1/y².

[x/﹙xy+y﹚]·[﹙x²+x﹚/x²y]
=[x/﹙y(x+1﹚]·[x﹙x+1﹚/x²y]
=1/y(x+1)*(x+1)/y
=1/y²
如果本题有什么不明白可以追问,