1.已知多项式kx²-6xy-8y²可分解为2(mx+y)(x-4y),求k,m的值.
问题描述:
1.已知多项式kx²-6xy-8y²可分解为2(mx+y)(x-4y),求k,m的值.
2.解方程:(3x-10)²=(2-5x)²
答
1.已知多项式kx²-6xy-8y²可分解为2(mx+y)(x-4y),求k,m的值.把2(mx+y)(x-4y)展开成多项式:2mx²+2(1-4m)xy -8y²对比 kx²-6xy-8y²我们知道:2m=k,2(1-4m)= -6 ,解得:k=2,m=1 (这个...