求二重积分∫∫dxdy/(x-y)^2dxdy ,1
问题描述：
求二重积分∫∫dxdy/(x-y)^2dxdy ,1
答
I =∫∫dxdy/(x-y)^2 =∫dx∫dy/(y-x)^2
=∫dx[-1/(y-x)] =∫[-1/(4-x)+1/(3-x)]dx
= [ln(4-x)-ln(3-x)]2ln2-ln3=ln(4/3).
请再核对一下答案.