tan(派/4+a)=1/2,tan(b-派/4)=1/3则tan(a+b)=?

问题描述:

tan(派/4+a)=1/2,tan(b-派/4)=1/3则tan(a+b)=?

tan(a+b)
=tan[(a+π/4)+(b-π/4)]
=[tan(a+π/4)+tan(b-π/4)]/[1-tan(a+π/4)tan(b-π/4)]
=(1/2+1/3)/(1-1/2*1/3)
=(5/6)/(5/6)
=1