(x+3)²-(x-3)×(x-5)=16
问题描述：
(x+3)²-(x-3)×(x-5)=16
答
答：
(x+3)²-(x-3)(x-5)=16
(x+3)²-16=(x-3)(x-5)
(x+3-4)(x+3+4)=(x-3)(x-5)
(x-1)(x+7)=(x-3)(x-5)
x²+6x-7=x²-8x+15
14x=22
x=11/7