(x²+3)(ax²-1)的乘积中不含x²项,那么a=

问题描述:

(x²+3)(ax²-1)的乘积中不含x²项,那么a=

(x²+3)(ax²-1)
=ax^4-x²+3ax²-3
=ax^4+(3a-1)x²-3
不含x²项,即3a-1=0,所以a=1/3