设多项式ax5+bx3+cx+d=M,已知当x=0时,M=-5;当x=-3时,M=7;则: (1)d=_; (2)当x=3时,M=_.
问题描述:
设多项式ax5+bx3+cx+d=M,已知当x=0时,M=-5;当x=-3时,M=7;则:
(1)d=______;
(2)当x=3时,M=______.
答
(1)x=0时,d=M=-5;
(2)x=-3时,ax5+bx3+cx+d=-243a-27b-3c-5=7,
解得-243a-27b-3c=12,
x=3时,ax5+bx3+cx+d=243a+27b+3c-5=-12-5=-17.
故答案为:-5;-17.