y=sin(2x+π/4)的单调区间
问题描述:
y=sin(2x+π/4)的单调区间
答
∵y=sint在 [-π/2+2kπ,π/2+2kπ]递增 令2x+π/4=t ∴-π/2+2kπ≤2x+π/4≤π/2+2kπ
-3π/8+kπ≤x≤π/8+kπ 递增 同理可求递减.