f(x)=sin2x-2sin^2x*sin2x

问题描述:

f(x)=sin2x-2sin^2x*sin2x
最小正周期等于多少?

f(x)=sin2x-2sin²x*sin2x=sin2x-(1-cos2x)sin2x=sin2xcos2x=sin4x/2
T=2π/4=π/2