若sin(π6−α)=13,则2cos2(π6+α2)−1等于(  ) A.−79 B.−13 C.79 D.13

问题描述:

sin(

π
6
−α)=
1
3
,则2cos2(
π
6
+
α
2
)−1等于(  )
A.
7
9

B.
1
3

C.
7
9

D.
1
3

sin(

π
6
−α)=
1
3
,则2cos2(
π
6
+
α
2
)−1=cos(α+
π
3
)=cos[
π
2
−(
π
6
−α)
]=sin(
π
6
−α
)=
1
3

故选D