(1)已知f(-x)+2f(x)=2x+2,求f(x)

问题描述:

(1)已知f(-x)+2f(x)=2x+2,求f(x)
(2)已知函数满足f(x-1/x)=(x+1/x)的平方,求f(x)和f(x+1)

f(-x)+2f(x)=2x+2f(x)+2f(-x)=-2x+2两者相加得f(x)+f(-x)=4/3两者相减得f(x)-f(-x)=4x得 f(x)=2x+2/3f(x-1/x)=(x+1/x)^2=x^2+2+1/x^2=(x-1/x)^2+4所以 f(x)=x^2+4f(x+1)=(x+1)^2+4=x^2+2x+5...