如图所示,电阻R1的阻值为10Ω,R2的阻值为20Ω,用电压表测得R1两端的电压为3v,求电源电压
问题描述:
如图所示,电阻R1的阻值为10Ω,R2的阻值为20Ω,用电压表测得R1两端的电压为3v,求电源电压
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答
先求串联电路的电流I:I=U1/R1=0.3A,
则串联电路的总电压即电源电压为:U=I(R1+R2)=0.3A(10Ω+20Ω)=9V