已知复数z满足(z-2)i=1+i(i为虚数单位),则z的模为_.

问题描述:

已知复数z满足(z-2)i=1+i(i为虚数单位),则z的模为______.

∵复数z满足(z-2)i=1+i(i为虚数单位),∴z=2+

1+i
i
=2+
(−i)(1+i)
i2
 
=2+1-i=3-i,∴|z|=
9+1
=
10

故答案为:
10