x>=0 f(x)=ax+b；x
问题描述：
x>=0 f(x)=ax+b；x
答
f(x)=ax+b ; x>=0=arctan(1/x)+e^(1/x) ; x0+)f(x) = lim(x->0+) ax+b= blim(x->0-)f(x) = lim(x->0-)arctan(1/x)+e^(1/x)=-π/2f(0+)=f(0-)=>b= -π/2f'(0+)=af'(x-) = -1/[x^2(x^2+1)] -(1/x^2)e^(1/x) f'(0-) = -...