(b-2a)^2÷(-b/a)*(-3b/4a)^3 (x-1/x+2)*(x^2-4/x^2-2x+1)÷1/x^2-1
问题描述：
(b-2a)^2÷(-b/a)*(-3b/4a)^3 (x-1/x+2)*(x^2-4/x^2-2x+1)÷1/x^2-1
(b-2a)^2÷(-b/a)*(-3b/4a)^3
(x-1/x+2)*(x^2-4/x^2-2x+1)÷1/x^2-1
答
(b-2a)^2÷(-b/a)*(-3b/4a)^3
=(2a-b)²×(-a/b)×(-27b³/64a³)
=27b²(2a-b)²/64a²
(x-1/x+2)*(x^2-4/x^2-2x+1)÷1/x^2-1
=(x-1)/(x+2)× (x+2)(x-2)/(x-1)² ×(x+1)(x-1)
=(x-2)(x+1)
=x²-x-2Sorry，第一题题目打错了，应该是(b/2a)^2÷(-b/a)*(-3b/4a)^3(b/2a)^2÷(-b/a)*(-3b/4a)^3=b²/4a²×(-a/b)×(-27b³/64a³)=27b的次方/256a的4次方