a²-b²-c²+2bc因式分解

问题描述:

a²-b²-c²+2bc因式分解

a²-b²-c²+2bc=a²-(b²+c²-2bc)=a²-(b-c)²=(a+b-c)(a-b+c)

(a-b+c)(a+b-c)

=(a-b+c)(a+b-c)

a²-b²-c²+2bc
=a²-(b²+c²-2bc)
=a²-(b-c)²
=[a-(b-c)]*[a+(b-c)]
=(a-b+c)*(a+b-c)

a²-b²-c²+2bc
=a²-(b²-2bc+c²)
=a²-(b-c)²
=(a+b-c)(a-b+c)