已知/a+2/+{b+1/4}²=0,求(a²b-2ab)-(3ab²+4ab)的值.

问题描述:

已知/a+2/+{b+1/4}²=0,求(a²b-2ab)-(3ab²+4ab)的值.

已知/a+2/+{b+1/4}²=0,则 a+2=0 a=-2b+1/4==0 b=-1/4(a²b-2ab)-(3ab²+4ab)=a²b-2ab-3ab²-4ab=a²b-3ab²-6ab=ab(a-3b-6) a=-2 b=-1/4=1/2(-2+3/4-6)=-1+3/8-3=-...