已知数列｛an｝的通项公式为an=log2（n+1/n+2）(n∈N*),设其前n项和为Sn,则使Sn
问题描述：
已知数列｛an｝的通项公式为an=log2（n+1/n+2）(n∈N*),设其前n项和为Sn,则使Sn
答
a1=log2 2/3 a2=log2 3/4.
a1+a2+...an=log2 (2/3)(3/4)(4/5)...(n+1/n+2)
=log2 2/(n+2)=Sn
sn