求(tan70°-tan10°+tan120°)/(tan70°tan10°)的值

问题描述:

求(tan70°-tan10°+tan120°)/(tan70°tan10°)的值

tan6o°=tan(70°-10°)=(tan70°-tan10°)/(1-tan70°tan10)代入上式即可

tan70°-tan10°+ tan120°
-----------------------
tan70°tan10°
tan(70°-10°)(1+tan70°tan10°)+tan120°
= ---------------------------------------------
tan70°tan10°
tan60°(tan70°tan10°+1)+ tan120°
= ----------------------------------------
tan70°tan10°
__
__ √3 + tan120°
= √3 + ------------------
tan70°tan10°
__
__ √3 + tan(2×60°)
= √3 + -------------------
tan70°tan10°
__ __
__ √3 -√3
= √3 + -----------------
tan70°tan10°
__
= √3