-2xy-x²-y² (x²-2y)²-(1-2y)² 分解因式

问题描述:

-2xy-x²-y² (x²-2y)²-(1-2y)² 分解因式

(x²-2y)²-(1-2y)²
=(x²-2y+1-2y)(x²-2y-1+2y)
=(x²-4y+1)(x²-1)
=(x²-4y+1)(x+1)(x-1)

-2xy-x²-y²=-(x²+2xy+y²)=-(x+y)²(x²-2y)²-(1-2y)²=(x²-2y+1-2y)(x²-2y-1+2y)=(x²-4y+1)(x²-1)=(x²-4y+1)(x+1)(x-1)