xy满足(x-5)的绝对值=8x-y²-16

问题描述:

xy满足(x-5)的绝对值=8x-y&sup2-16

(x-5)^2=8y-y^2-16
(x-5)^2=-(y-4)^2
(x-5)^2+(y-4)^2=0
由于平方项恒非负,因此两平方项均=0
x-5=0 x=5
y-4=0 y=4
x=5 y=4