等差数列{an}中,a3+a5=24,a2=3,则a6=_.

问题描述:

等差数列{an}中,a3+a5=24,a2=3,则a6=______.

∵a3+a5=24,a2=3

2a1+6d=24
a1+d=3

解方程可求,a1=
3
2
,d=
9
2

∴a6=a1+5d=
3
2
+
45
2
=21.
故答案为:21