函数y=sin(x-兀/12)cos(x-兀/12)图象的对称中心坐标是?

问题描述:

函数y=sin(x-兀/12)cos(x-兀/12)图象的对称中心坐标是?

sin(x-兀/12)cos(x-兀/12)=1/2sin(2x-pi/6)
2x-pi/6= kpi+pi/2