计算:3的½次方×12的1/6次方×2/3的⅓次方=?

问题描述:

计算:3的½次方×12的1/6次方×2/3的⅓次方=?
给力啊 要我把悬赏抬高点吗

原式 = [ 3^(1/2)]X[(3X4)^(1/6)]X[(2/3)^(1/3)]
= [3^(1/2+1/6-1/3)]X[(2X2)^(1/6)]X[2^(1/3)]
= [3^(1/3)]X[2^(1/6+1/6+1/3)]
= [3^(1/3)]X[2^(2/3)]
= [3^(1/3)]X[2^(1/3)]X[2^(1/3)]
= (3X2X2)^(1/3)
= 12^(1/3)
不知道我这样写你是否能看懂,不过这已经是一步一步写到做后的结果了,