若角α的终边与角π/6的终边关于直线y=x对称,且α∈(-4π,4π),则α=?

问题描述:

若角α的终边与角π/6的终边关于直线y=x对称,且α∈(-4π,4π),则α=?

因为π/3的终边与π/6的终边关于直线y=x对称,所以角a=2kπ+π/3,k属于Z,又因为a属于(-4π,4π),所以k=-2,-1,0,1时,角a=-11π/3,-5π/3,π/3,7π/3