①已知x^2+y^2-6x-2y+10=0,则1/x+1/y= ②已知a+b=1,a^2+b^2=2,则a^3+b^3=

问题描述:

①已知x^2+y^2-6x-2y+10=0,则1/x+1/y= ②已知a+b=1,a^2+b^2=2,则a^3+b^3=

①x²+y²-6x-2y+10=0(x-3)²+(y-1)²=0x=3,y=11/x+1/y=4/3②a³+b³ =(a+b)(a²-ab+b²)(a+b=1) =a²-ab+b²(a+b)²=a²+b²+2ab=1a²+b²...