跪求 计算cos(-25π/12)的值,谢谢
问题描述:
跪求 计算cos(-25π/12)的值,谢谢
答
cos(-25π/12)=cos(1/12π)=cos(15°)=cos(45°-30°)=cos30°cos45°+sin30°sin45°=4分之(根6加根2)
跪求 计算cos(-25π/12)的值,谢谢
cos(-25π/12)=cos(1/12π)=cos(15°)=cos(45°-30°)=cos30°cos45°+sin30°sin45°=4分之(根6加根2)