设向量a1=(0 2 1),a2=(-1 0 3),a3=(1 2 0),则 -a1-1/2a2+3/2a3=多少
问题描述:
设向量a1=(0 2 1),a2=(-1 0 3),a3=(1 2 0),则 -a1-1/2a2+3/2a3=多少
答
-a1-1/2a2+3/2a3=(2,1,-5/2)
设向量a1=(0 2 1),a2=(-1 0 3),a3=(1 2 0),则 -a1-1/2a2+3/2a3=多少
-a1-1/2a2+3/2a3=(2,1,-5/2)