设F(X)=sin(πx/4-π/6)-2cos(πx/8)2+1求最小正周期
问题描述:
设F(X)=sin(πx/4-π/6)-2cos(πx/8)2+1求最小正周期
答
f(x)=sin(πx/4-π/6)-[2cos²(πx/8)-1]=sin(πx/4-π/6)-cos(πx/4)=sin(πx/4)cos(π/6)-cos(πx/4)sin(π/6)-cos(πx/4)=根号3/2sin(πx/4)-(1/2)cos(πx/4)-cos(πx/4)=根号3/2sin(πx/4)-(3/2)cos(πx...