化简{2sin50°+cos10°(1+(√3)tan10°)}/√(1-(sin^2)5°)
问题描述:
化简{2sin50°+cos10°(1+(√3)tan10°)}/√(1-(sin^2)5°)
答
2(√2)原式={2sin50°+cos10°+√3sin10°}/cos5°={2sin50°+2[1/2cos10°+√3/2sin10°]}/cos5°={2sin50°+2[sin30°cos10°+cos30°sin10°}/cos5°={2sin50°+2sin(30°+10°)}/cos5°=2{sin50°+sin40°}/cos5...