2sin(-2x+π/6)的单调区间怎么求

问题描述:

2sin(-2x+π/6)的单调区间怎么求

先将x前的系数转化为正数,y=2sin(-2x+π/6)=-2sin(2x-π/6)(1)增区间即 y=2sin(2x-π/6)的减区间∴ 2kπ+π/2≤2x-π/6≤2kπ+3π/2∴ 2kπ+2π/3≤2x≤2kπ+5π/3∴ kπ+π/3≤x≤kπ+5π/6即增区间是[kπ+π/3,k...