求y=tan(2x+π/3) 1.定义域 20单调递增区间
问题描述：
求y=tan(2x+π/3) 1.定义域 20单调递增区间
答
1、
2x+π/3 ≠kπ/2
2x≠kπ/2-π/3
x≠kπ/4-π/6
(k∈Z)
2、
2x+π/3∈(-kπ/2,kπ/2)
2x∈(-kπ/2-π/3,kπ/2-π/3)
x∈(-kπ/4-π/6,kπ/4-π/6)