求y=3sin(2x+π/4)的单调递增区间和y=3sin(2x+π/6)的单调递减区间

问题描述:

求y=3sin(2x+π/4)的单调递增区间和y=3sin(2x+π/6)的单调递减区间

y=sinx增区间[2kπ-π/2,2kπ+π/2]
所以本题,2kπ-π/2≤π/4+2x≤2kπ+π/2
kπ-3π/8