[(x^2+y^2)^2-4x^2y^2]÷(x^2-y^2)化简
问题描述:
[(x^2+y^2)^2-4x^2y^2]÷(x^2-y^2)化简
答
[(x^2+y^2)^2-4x^2y^2]÷(x^2-y^2)
= (x^2-2xy+y^2)(x^2-2xy+y^2)÷(x^2-y^2)
= (x-y)^2(x+y)^2÷(x^2-y^2)
= [(x-y)(x+y)]^2÷(x^2-y^2)
= (x^2-y^2)^2÷(x^2-y^2)
= x^2-y^2