函数f(x)=√3cos(-x/2)+sin(x/2-丌),x€R.求f(x)的最小正周期
问题描述:
函数f(x)=√3cos(-x/2)+sin(x/2-丌),x€R.求f(x)的最小正周期
答
f(x)=√3cos(-x/2)+sin(x/2-丌)
=√3cos(x/2)-sin(x/2)
=2[cos(x/2)cos(π/3)-sin(x/2)sin(π/3)]
=2cos(x/2+π/3)
T=2π/(1/2)=4π