化简tan(2π-α)sin(-2π-α)cos(6π-α)/cos(α-π)sin(5π-α)
问题描述:
化简tan(2π-α)sin(-2π-α)cos(6π-α)/cos(α-π)sin(5π-α)
答
tan(2π-α)sin(-2π-α)cos(6π-α)/cos(α-π)sin(5π-α)
=-tanα(-sinα)cosα/(-cosα)sinα
=-tanα