a>1,b>1,log2（a）*log2（b）=64,求log2(ab)最小值
问题描述：
a>1,b>1,log2（a）*log2（b）=64,求log2(ab)最小值
答
log2(ab)=log2(a)+log2(b)>=2根号[log2(a)log2(b)]=2根号64=16
因此当log2(a)=log2(b)时，log2(ab)达到最小值16
答
a＞1,b＞1,得 log2(a)＞0,log2(b)＞0
log2(a)*log(b)=64,则 log2(ab)=log2(a)+log(b)≥2根号64=16
当且仅当log2(a)=log2(b)=8 即 a=b=256 时,取最小值16