A,B的极坐标为(3,π/4)和(-3,π/12),求AB距离

问题描述:

A,B的极坐标为(3,π/4)和(-3,π/12),求AB距离

A,(3,π/4),B(-3,π/12)=(3,13π/12)
|OA|=|OB|=3
角AOB= 13π/12-π/4=5π/6
用余弦定理得:
AB=3√(2+√3)=3/2*(√6+√2)