设Sn=1*4+2*7+.n(3n+1)则Sn=

问题描述:

设Sn=1*4+2*7+.n(3n+1)则Sn=

Sn=1*4+2*7+.n(3n+1)
=3*1&sup2+1+3*2&sup2+2+...+3*n&sup2+n
=3*(1&sup2+2&sup2+...+n&sup2)+(1+2+...+n)
=3*n*(n+1)*(2n+1)/6+n*(n+1)/2
=n*(n+1)&sup2