u的导数关于du的不定积分,即:∫u'du=?例如:∫(x²)'dx²=?
问题描述:
u的导数关于du的不定积分,即:∫u'du=?例如:∫(x²)'dx²=?
答
∫(x²)'dx²
=∫(2x) (2xdx)
=4∫x^2dx
=(4/3)x^3 + C