若定义域为R的周期函数f(x)的周期是2π,且f(π/3)=1/2,则f(7π/3)=

问题描述:

若定义域为R的周期函数f(x)的周期是2π,且f(π/3)=1/2,则f(7π/3)=
π是180°

若定义域为R的周期函数f(x)的周期是2π,且f(π/3)=1/2
则f(7π/3)=f(2π+π/3)=f(π/3)=1/2