-sinx=cos((3π/2-x)

问题描述:

-sinx=cos((3π/2-x)
从-sinx推导

cos(3π/2-x)=cos(3π/2)cosx+sin(3π/2)sinx=-sinx
则:
-sinx=cos(3π/2-x)从-sinx推导下-sinx=0cosx-sinx=cos(3π/2)cosx+sin(3π/2)sinx=cos(3π/2-x)