3(t^2)-64t+256=0 怎么算?
问题描述:
3(t^2)-64t+256=0 怎么算?
答
(t-16)(3t-16)=0
所以t=16或t=16/3
3(t^2)-64t+256=0 怎么算?
(t-16)(3t-16)=0
所以t=16或t=16/3