若x,y∈R,(x+y)^2i+6i-x=-y+5(x+y)i-1,求x和y的值
问题描述：
若x,y∈R,(x+y)^2i+6i-x=-y+5(x+y)i-1,求x和y的值
答
(x+y)²i+6i-x=-y+5(x+y)i-1[(x+y)²+6]i-x=5(x+y)i-y-1则：(x+y)²+6=5(x+y) -x=-y-1 即：(x+y)²+6=5(x+y) ①x=y+1 ②把②代人①(y+1+y)²+6=5(y+1+y)(2y+1)²+6=5(2y+1)4y²+4y+1+6=...